Ordinary call
Minimum Attendance. It is necessary to attend a minimum of 80% of the labs.
Assessment of learning is done through a process of continuous assessment based on:
- Theory Mark (TM): This mark is composed of two parts:
- First exam (FE). About mid-semester there will be an exam in which approximately half of the theoretical content will be evaluated.
- Second exam (SE). Coinciding with the final exam of the ordinary call, there will be an exam in which approximately the second half of the theoretical content will be evaluated.
TM = 0.5 * FE + 0.5 * SE
However, students have the option to take SE with all the theoretical content of the whole course, so the final mark will be calculated as follows:
TM = SE
- Lab Mark (LM): This mark is composed of two parts:
- Continuous assessment of laboratory work (CAL). It is done by defending the work that has been carried out by each student during the whole academic year. The teacher will keep track of the work done by each student and may propose changes or additions to the developed tasks during lab sessions. It is necessary to have a minimum attendance of 80% and a minimum of 80% of the requested deliveries to obtain a mark in this part.
- Lab exam (LE).
- Students that DO NOT pass the continuous assessment in the labs but pass the theoretical exam, can take a final practical exam. This assessment will provide the whole laboratory mark. So, in this case: LM = LE
- On the other hand, all the students with continuous assessment of laboratory work CAL >= 5 may take an optional exam to get up to 3 extra points: LM = 0.7 * CAL + 0.3 * LE
Once both have been passed (TM and LM), the course is passed with the following final grade:
FG = 0.5 * TM + 0.5 * LM
In the event of not achieving any of the conditions required to pass the course, and having taken assessments weighted by at least 50% of the total weight of the course, the final grade will be calculated as:
FG = Minimum (4, 0.5 * TM + 0.5 * LM)
All partial marks of both theory and labs without delivery will be considered as 0 and the same formula will be applied.
If the student has passed any of the previous two parts (TM or LM), the mark is kept for the extraordinary call.
Extraordinary call and differentiated assessment model
There will be a written exam to obtain TM.
There will also be a practical exam with a computer to obtain LM.
If both are equal to or greater than 5, the course is passed with the following final grade:
FG = 0.5 * TM + 0.5 * LM
If either condition (TM>=5 or LM>=5) is not met, the final grade will be calculated as:
FG = Minimum (4, 0,5 * TM + 0,5 * LM)
Advance extraordinary call
No previous mark is kept, and the assessment exams will be conducted as in the extraordinary call.
Exceptionally, online evaluation activities might be established if the general health situation requires so. In that case, students will be informed in due course.